我有一个使用 Hibernate 的项目，但有一个错误表未映射。

org.jboss.resteasy.spi.UnhandledException: javax.ejb.EJBException: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: TrainingRoom is not mapped [SELECT DISTINCT t FROM TrainingRoom t ORDER BY t.id] 
at org.jboss.resteasy.core.ExceptionHandler.handleApplicationException(ExceptionHandler.java:77) 
at org.jboss.resteasy.core.ExceptionHandler.handleException(ExceptionHandler.java:220) 
at org.jboss.resteasy.core.SynchronousDispatcher.writeException(SynchronousDispatcher.java:175) 
... 
Caused by: javax.ejb.EJBException: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: TrainingRoom is not mapped [SELECT DISTINCT t FROM TrainingRoom t ORDER BY t.id] 
at org.jboss.as.ejb3.tx.CMTTxInterceptor.handleExceptionInOurTx(CMTTxInterceptor.java:187) 
at org.jboss.as.ejb3.tx.CMTTxInterceptor.invokeInOurTx(CMTTxInterceptor.java:277) 
at org.jboss.as.ejb3.tx.CMTTxInterceptor.required(CMTTxInterceptor.java:327) 
... 
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: TrainingRoom is not mapped [SELECT DISTINCT t FROM TrainingRoom t ORDER BY t.id] 
at org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79) 
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103) 
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:218) 
... 

这是我的 TrainingRoom.java

@Entity 
@Table(name = "ppp_trainingRoom") 
public class TrainingRoom { 
 
    @Id 
    @GeneratedValue(strategy = GenerationType.TABLE) 
    @Column(name = "id", updatable = false, nullable = false) 
    private Long id; 
 
    @Column 
    private String roomName; 
 
    //GET SET Method 
 
} 

TrainingRoomEndpoint.java

@Stateless 
@Path("/trainingRoom") 
public class TrainingRoomEndpoint { 
 
    @Inject 
    TrainingRoomService trainingRoomService; 
 
    @GET 
    @Path("/listAll") 
    @Produces("application/json") 
    public Response listAll(@Context HttpServletRequest request,     @QueryParam("start") Integer startPosition, @QueryParam("max") Integer     maxResult) { 
        List<TrainingRoom> trainingRoomList =     trainingRoomService.listAll(startPosition, maxResult); 
        return Response.status(200).entity(trainingRoomList).build(); 
    } 
} 

TrainingRoomService.java

public List<TrainingRoom> listAll(@QueryParam("start") Integer startPosition, 
        @QueryParam("max") Integer maxResult) { 
    logger.info(":: listAll ::"); 
    TypedQuery<TrainingRoom> findAllQuery = em.createQuery( 
            "SELECT DISTINCT t FROM TrainingRoom t ORDER BY t.id", TrainingRoom.class); 
    if( startPosition != null ) { 
        findAllQuery.setFirstResult(startPosition); 
    } 
    if( maxResult != null ) { 
        findAllQuery.setMaxResults(maxResult); 
    } 
    final List<TrainingRoom> results = findAllQuery.getResultList(); 
    return results; 
} 

在遇到此错误之前，我有 2 个 EntityManager，因为我有一些同义词表。但我发现其实没有必要。所以我删除了它，然后像上面的错误一样卡住了。

我该如何解决这个问题？

提前谢谢

请您参考如下方法:

您可以添加新属性:

 <property name="hibernate.archive.autodetection" value="class" />   

或者您可以在持久单元标记下为每个类指定类标记:

<class>org.cmh.itsetup.model.TrainingRoom</class>